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  EXHIBITOR BOOKING FORM

Booking a Solutions Workshop Speaking Slot From the Solutions Workshop Speaking Slot table (see the Exhibition Information document) identify the speaking slot number and corresponding time in order of preference. Preference Speaking Slot Number/Day/Presentation Time 1st choice Speaking slot number: ______ Day: __________________ Time: ________ 2nd choice Speaking slot number: ______ Day: __________________ Time: ________ 3rd choice Speaking slot number: ______ Day: __________________ Time: ________ 4. Confirmation If the requested exhibition space and/or the Solutions Workshop speaking slot is still available, ICAO will confirm the booking by return e-mail or facsimile.

Score: 1216397.5 - https://www.icao.int/Meetings/...S2012-ExhibitorBookingForm.doc

  EXHIBITOR BOOKING FORM

Booking a Solutions Workshop Speaking Slot From the Solutions Workshop Speaking Slot table (see the Exhibition Information document) identify the speaking slot number and corresponding time in order of preference. Preference Speaking Slot Number/Day/Presentation Time 1st choice Speaking slot number: ______ Day: __________________ Time: ________ 2nd choice Speaking slot number: ______ Day: __________________ Time: ________ 3rd choice Speaking slot number: ______ Day: __________________ Time: ________ 4. Confirmation If the requested exhibition space and/or the Solutions Workshop speaking slot is still available, ICAO will confirm the booking by return e-mail or facsimile.

Score: 1216397.5 - https://www.icao.int/Meetings/...C2012-ExhibitorBookingForm.doc

  Page 186 - Kaleidoscope Academic Conference Proceedings 2020

By using the Dijkstra’s shortest path algorithm, we Intuitively, the RSRP series in the LEO network has strong can find the longest path from the first time slot to the last regularity, so a relatively simple neural network structure time slot, which is actually the optimal handover strategy for should be chosen to reduce the training time and prevent this UE. overfitting. (...) Actually, in the simulation the number of beams for a long period, then the method in Subsection considered beams in each time slot is set to be 10. The length 3.1.2 can be used to find the optimal handover strategy. of a time slot is set to be 0.5s and the RSRP values in the However, in most cases a UE only knows its historical RSRP. previous 10 time slots are used to form the input. (...) For every UE in every time slot, the previous 10 RSRP for handover decisions.

Score: 1213282 - https://www.itu.int/en/publica.../files/basic-html/page186.html

  ECOSOC OPERATIONAL A

TARGET AUDIENCE AND OUTREACH: PREFERRED DAY & TIME: [please provide at least 2 options] · Slot 1: Tue 17 May, 8:30 – 9:45am · Slot 2: Tue 17 May, 1:15 – 2:45pm · Slot 3: Wed 18 May, 1:15 – 2:45pm · Slot 4: Thu 19 May, 1:15 – 2:45pm PRIMARY CONTACT PERSON: · Name · Title · Section/Division · Email · Telephone OTHER NOTES/COMMENTS:

Score: 1212471.3 - https://www.un.org/ecosoc/site...c/OAS2022-SideEvents-Form.docx

  Page 1116 - 5G Basics - Core Network Aspects

ODTUjk and ODTUk.ts signals are directly time- division multiplexed into the tributary slots of an OPUk. A mixture of p (p  10n) ODU0, q (q 10n) ODU1, r (r  10n) ODU2, s (s  10n) ODU2e, t (t int(10n/4)) ODU3, u (u  n) ODU4 and v (v  10n) ODUflex signals can be multiplexed into an ODTUGCn (PT=22) using time-division multiplexing. (...) ODTUjk and ODTUk.ts signals are directly time-division multiplexed into the tributary slots of an OPUk. ODTUCn.ts signals are directly time-division multiplexed into the tributary slots of an OPUCn. (...) Table 7-10 – Overview of ODUj into OPUk and ODUk into OPUCn mapping types 5G tributary slots 2.5G tributary slots 1.25G tributary slots OPUCn OPU2 OPU3 OPU1 OPU2 OPU3 OPU4 (PT=22) (PT=20) (PT=20) (PT=20) (PT=21) (PT=21) (PT=21) ODU0 GMP - Note – – AMP GMP GMP GMP ODU1 GMP - Note AMP AMP – AMP AMP GMP ODU2 GMP – AMP – – AMP GMP ODU2e GMP – – – – GMP GMP ODU3 GMP – – – – – GMP ODU4 GMP – – – – – – ODUflex GMP – – – GMP GMP GMP NOTE – Mapping ODU0 and ODU1 into a 5G tributary slot of the OPUCn does not fully occupy the tributary slot’s bandwidth.

Score: 1212330.8 - https://www.itu.int/en/publica...files/basic-html/page1116.html

  Page 104 - Kaleidoscope Academic Conference Proceedings 2020

In section 3, the proposed design of DPCI, ROPC and the dynamic selection slot n slot n+1 slot n+2 mechanism is described in detail. (...) SERVICE MULTIPLEXING SYSTEM MODEL slot n slot n+1 slot n+2 A 5G new radio (NR) uplink system is considered for this work, where there are N cells, each equipped with Kr mini-slot m mini-slot m+1 mini-slot m+2 mini-slot m+3 receiving antennas, and randomly distributed M UEs, each eMBB UE arrival 6 7 8 9 equipped with Kt transmitting antennas. (...) The monitoring = + + 0 (2) −1 periodicity of UL cancellation signaling should be equal to the URLLC physical downlink control channel (PDCCH) monitoring interval, i.e. mini-slot level [15]. In frequency Where, H1 represents the channel matrix from the service cell domain, the smallest scheduling unit is the resource block to the receiver, H2 represents the channel matrix from the (RB), which is composed of 12 resource elements (RE). interference cell to the receiver.

Score: 1212153.1 - https://www.itu.int/en/publica.../files/basic-html/page104.html

  Capacity building: Forest Sector Outlook Modelling and its Practical Use | UNECE

Werner Kurz   PDF PDF Slot 7: Forest Resource Modelling in Finland Dr. (...) Hannu Hirvelä  PDF PDF Slot 8: Forest Resource Modelling in Switzerland Dr. (...) Mart-Jan Schelhaas  PDF   PDF Slot 11: Forest Resource Modelling in the US  Dr.

Score: 1212051.8 - https://unece.org/forests/even...odelling-and-its-practical-use

  Page 1200 - 5G Basics - Core Network Aspects

An OPU1 is divided into two 1.25G tributary slots numbered 1 to 2. – An OPU1 1.25G tributary slot occupies 50% of the OPU1 payload area. (...) The tributary slot overhead (TSOH) of OPU1 tributary slots is located in column 16 plus column 15, rows 1, 2 and 3 of the OPU1 frame. The TSOH for a 1.25G tributary slot is available once every 2 frames. A 2-frame multiframe structure is used for this assignment.

Score: 1211058.8 - https://www.itu.int/en/publica...files/basic-html/page1200.html

  Page 1220 - 5G Basics - Core Network Aspects

The MSI indicates the ODTU content of each tributary slot of an OPU. One byte is used for each tributary slot. – The ODTU type in bits 1 and 2 indicates if the OPU3 1.25G TS is carrying an ODTU13, ODTU23 or ODTU3.ts. The default ODTU type is 11 (unallocated); it is present when a tributary slot is not allocated to carry an ODTU. – The tributary port # in bits 3 to 8 indicates the port number of the ODTU that is being transported in this TS; a flexible assignment of tributary ports to tributary slots is possible, ODTU13 tributary ports are numbered 1 to 16, ODTU23 tributary ports are numbered 1 to 4 and ODTU3.ts tributary ports are numbered 1 to 32. The value is set to all-0s when the ODTU type has the value 11 (tributary slot is unallocated). 1210     1215     1216     1217     1218     1219     1220     1221     1222     1223     1224     1225          

Score: 1209343.1 - https://www.itu.int/en/publica...files/basic-html/page1220.html

  Page 1241 - 5G Basics - Core Network Aspects

The MSI has a fixed length of 40n bytes and indicates the ODTU content of each tributary slot (TS) of an OPUCn. Two bytes are used for each TS. 20.4.1.1 OPUCn multiplex structure identifier (MSI) – Payload type 22 For the 20n OPUCn 5G tributary slots n times 40 bytes of the PSI are used (named PSI[x.y] where x = 1…n and y = 2…41, that is PSI[1.2], PSI[1.3],…PSI[1.41], PSI[2.2], PSI[2.3],…, PSI[2.41], PSI[3.2],…,PSI[n-1.41], PSI[n.2]…, PSI[n.41]) as MSI bytes as shown in Figure 20-7. The MSI indicates the ODTU content of each tributary slot of an OPU. Two bytes are used for each tributary slot as illustrated in Figure 20-8 and the encoding of the fields of each MSI instance is illustrated in Figure 20-9. – The TS availability bit 1 indicates if the tributary slot is available or unavailable. – The TS occupation bit 9 indicates if the tributary slot is allocated or unallocated. – The tributary port # in bits 2 to 8 and 10 to 16 indicates the port number of the ODTUCn.ts that is being transported in this TS; a flexible assignment of tributary port to tributary slots is possible. (...) The value is set to all-0s when the occupation bit has the value 0 (tributary slot is unallocated). 1231     1236     1237     1238     1239     1240     1241     1242     1243     1244     1245     1246          

Score: 1208291.1 - https://www.itu.int/en/publica...files/basic-html/page1241.html